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9x^2-700=0
a = 9; b = 0; c = -700;
Δ = b2-4ac
Δ = 02-4·9·(-700)
Δ = 25200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{25200}=\sqrt{3600*7}=\sqrt{3600}*\sqrt{7}=60\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{7}}{2*9}=\frac{0-60\sqrt{7}}{18} =-\frac{60\sqrt{7}}{18} =-\frac{10\sqrt{7}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{7}}{2*9}=\frac{0+60\sqrt{7}}{18} =\frac{60\sqrt{7}}{18} =\frac{10\sqrt{7}}{3} $
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